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Jul 18, 2022 at 11:43 history edited Daniele Tampieri CC BY-SA 4.0
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Jul 18, 2022 at 1:05 history edited Yuval Peres CC BY-SA 4.0
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Jul 18, 2022 at 0:00 comment added Nate River I guess this works because the sup in the maximal function is realised closer and closer to $0$ as $x \to 0$. Furthermore for the failure to be in $L^1$ it needs only not be locally integrable near a point (in this case $0$).
Jul 17, 2022 at 23:57 comment added Nate River Very nice, I would not have come up with a function like that myself!
Jul 17, 2022 at 23:57 vote accept Nate River
Jul 17, 2022 at 23:32 history edited Yuval Peres CC BY-SA 4.0
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Jul 17, 2022 at 23:16 history edited Yuval Peres CC BY-SA 4.0
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Jul 17, 2022 at 16:31 comment added Nate River Interesting, I would’ve thought $g_n \to 0$ uniformly would cause you to be unable to capture the maximal function, since most of the points don’t get to “do what they want”. Looking forward to the counterexample!
Jul 17, 2022 at 15:56 history answered Yuval Peres CC BY-SA 4.0