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Equidistace Equidistant points on a compact Riemannian manifold

Let $(M,g)$ be a compact Riemannian manifold. To this Riemannian manifold, we associate a natural number $K(M,g)$ as follows:

$K(M,g)$ is the maximum of all $n\in \mathbb{N}$ such that we have at least $n$ distinct points $x_1,x_2,\ldots,x_n\in M$ such that $d(x_i,x_j)$ is independent of $i,j$$i\neq j$.

What is this number for the round sphere $S^n$?

Does $K(M,g)$ depends on the Riemannian metric $g$?

Equidistace points on a compact Riemannian manifold

Let $(M,g)$ be a compact Riemannian manifold. To this Riemannian manifold, we associate a natural number $K(M,g)$ as follows:

$K(M,g)$ is the maximum of all $n\in \mathbb{N}$ such that we have at least $n$ distinct points $x_1,x_2,\ldots,x_n\in M$ such that $d(x_i,x_j)$ is independent of $i,j$.

What is this number for the round sphere $S^n$?

Does $K(M,g)$ depends on the Riemannian metric $g$?

Equidistant points on a compact Riemannian manifold

Let $(M,g)$ be a compact Riemannian manifold. To this Riemannian manifold, we associate a natural number $K(M,g)$ as follows:

$K(M,g)$ is the maximum of all $n\in \mathbb{N}$ such that we have at least $n$ distinct points $x_1,x_2,\ldots,x_n\in M$ such that $d(x_i,x_j)$ is independent of $i\neq j$.

What is this number for the round sphere $S^n$?

Does $K(M,g)$ depends on the Riemannian metric $g$?

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Ali Taghavi
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Let $(M,g)$ be a compact Riemannian manifold. To this Riemannian manifold, we associate a natural number $K(M,g)$ as follows:

$K(M,g)$ is the maximum of all $n\in \mathbb{N}$ such that we have at least $n$ distinct ponitspoints $x_1,x_2,\ldots,x_n\in M$ such that $d(x_i,x_j)$ is independent of $i,j$.

What is this number for the round sphere $S^n$?

Does $K(M,g)$ depends on the Riemannian metric $g$?

Let $(M,g)$ be a compact Riemannian manifold. To this Riemannian manifold, we associate a natural number $K(M,g)$ as follows:

$K(M,g)$ is the maximum of all $n\in \mathbb{N}$ such that we have at least $n$ distinct ponits $x_1,x_2,\ldots,x_n\in M$ such that $d(x_i,x_j)$ is independent of $i,j$.

What is this number for the round sphere $S^n$?

Does $K(M,g)$ depends on the Riemannian metric $g$?

Let $(M,g)$ be a compact Riemannian manifold. To this Riemannian manifold, we associate a natural number $K(M,g)$ as follows:

$K(M,g)$ is the maximum of all $n\in \mathbb{N}$ such that we have at least $n$ distinct points $x_1,x_2,\ldots,x_n\in M$ such that $d(x_i,x_j)$ is independent of $i,j$.

What is this number for the round sphere $S^n$?

Does $K(M,g)$ depends on the Riemannian metric $g$?

Source Link
Ali Taghavi
  • 356
  • 8
  • 31
  • 123

Equidistace points on a compact Riemannian manifold

Let $(M,g)$ be a compact Riemannian manifold. To this Riemannian manifold, we associate a natural number $K(M,g)$ as follows:

$K(M,g)$ is the maximum of all $n\in \mathbb{N}$ such that we have at least $n$ distinct ponits $x_1,x_2,\ldots,x_n\in M$ such that $d(x_i,x_j)$ is independent of $i,j$.

What is this number for the round sphere $S^n$?

Does $K(M,g)$ depends on the Riemannian metric $g$?