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Feb 5, 2022 at 11:09 history edited YCor CC BY-SA 4.0
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Feb 5, 2022 at 11:06 history edited Ola Sande CC BY-SA 4.0
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Feb 5, 2022 at 10:48 history edited Ola Sande CC BY-SA 4.0
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Feb 5, 2022 at 10:27 comment added Maxime Ramzi Note that it's grouplike $\mathbb E_\infty$ spaces that are equivalent to connective spectra.
Feb 5, 2022 at 3:27 comment added dhy I'm not sure that this question is appropriate for MO, but here is a quick answer: This is not elliptic cohomology, actually, this is a sum of two copies of ordinary singular cohomology with coefficients in $\mathbb{Z}$ (with an index shift by $1$). The reason is that the homotopy type of an elliptic curve is $S^1\times S^1$, and $S^1$ is the Eilenberg-Maclane space $K(\mathbb{Z},1)$.
Feb 5, 2022 at 3:24 comment added dhy Crossposted from Math.SE: math.stackexchange.com/questions/4374022/…. (In the future, please note MSE crossposts in the original question to avoid duplication of effort.)
S Feb 5, 2022 at 3:12 review First questions
Feb 5, 2022 at 3:13
S Feb 5, 2022 at 3:12 history asked Ola Sande CC BY-SA 4.0