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May 29, 2023 at 5:32 comment added Nate River Something is wrong with what I wrote above, but I can’t tell what…
May 29, 2023 at 2:22 comment added Nate River I have read the linked paper, and have a question about the result for Brownian motion - isn’t it true that Theorem 4.3 implies that the result for Brownian motion may be extended to the critical $\beta = \alpha$ case? Specifically, using the fact that the BM is in $\mathcal A_n (\gamma, 2)$ for all $\gamma < \alpha$ and large enough $n$, and sending $\gamma \to \alpha^-$, we deduce that almost surely there exists no set $A$ on which the BM is $\alpha$ Hölder continuous and $\bar{\text{dim}}_M (A) > 1 - \alpha$. I may be making a mistake though…
Feb 6, 2022 at 19:49 comment added Yuval Peres No, the set $S$ in the Theorem is allowed to be random (and depend on the BM).
Feb 6, 2022 at 5:11 comment added Nate River I see! Though there is actually one subtlety - the set on which $B_t = A_t$ is random, while in the theorem $S$ is deterministic. Does this affect anything at all?
Feb 5, 2022 at 16:43 comment added Yuval Peres This is not discussed in the book- the relevant work was done well after the book was published.
Feb 4, 2022 at 7:17 comment added Nate River Ah, I wonder if I had missed this in your Brownian motion book…
Feb 4, 2022 at 7:17 vote accept Nate River
Feb 4, 2022 at 5:36 history answered Yuval Peres CC BY-SA 4.0