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Oct 23, 2021 at 23:19 vote accept Julian Newman
Oct 22, 2021 at 22:47 answer added Yuval Peres timeline score: 10
Oct 22, 2021 at 5:56 answer added Anthony Quas timeline score: 5
Oct 22, 2021 at 2:11 history edited Julian Newman CC BY-SA 4.0
added clarity to proof of BET
Oct 22, 2021 at 1:35 history edited Julian Newman CC BY-SA 4.0
added clarity to proof of BET
Oct 22, 2021 at 1:21 comment added Julian Newman I've now added the short proof of Birkhoff's ergodic theorem for bounded observables.
Oct 22, 2021 at 1:20 history edited Julian Newman CC BY-SA 4.0
Added "in the appropriate manner"
Oct 22, 2021 at 0:29 comment added Julian Newman @KConrad Yes - I can take a closer look, but even that proof seemed significantly more involved than the proof I currently have for the case of bounded observables.
Oct 21, 2021 at 23:41 comment added KConrad Have you looked at the paper of Katznelson and Weiss "A Simple Proof of Some Ergodic Theoems" (Israel J. Math.) 42 (1982), 291-296? Roughly speaking, it involves replacing an $L^1$-function $f$ with $\min(f,M)$ for a positive constant $M$, which amounts to replacing $f$ with a certain bounded $L^1$-function.
Oct 21, 2021 at 23:20 comment added Julian Newman @AnthonyQuas Even in the former case, although that technically wouldn't fulfil what I've asked, I'm still very interested, as the very short proof that I have in mind for bounded observables already basically consists of proving a suitable version of the maximal ergodic theorem (from which the result then follows immediately by making a simple choice of function to which to apply that maximal ergodic theorem)
Oct 21, 2021 at 23:12 history edited Julian Newman CC BY-SA 4.0
added condition
Oct 21, 2021 at 23:09 comment added Julian Newman @AnthonyQuas Is this maximal ergodic theorem specifically for $P_n$ being the $n$-th Birkhoff average under a measure-preserving transformation, or is it for any sequence of Markov operators fulfilling the conditions I described?
Oct 21, 2021 at 23:01 comment added Anthony Quas I'm guessing you don't consider the use of the maximal ergodic theorem to be elementary. One formulation of the maximal ergodic theorem is that the subset of $L^1$ consisting of those functions for which $P_nf$ converges pointwise is closed.
Oct 21, 2021 at 21:38 history asked Julian Newman CC BY-SA 4.0