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Aug 16, 2021 at 14:17 comment added Kurt G. Because $p(t;x,y)=\frac{1}{\sqrt{2\pi t}}\exp[-\frac{(y-x)^2}{2t}]$ the equation I wrote is (19). Secondly, the unreflected BM is $x_t$ and the reflected one is $|x_t|\,.$
Aug 16, 2021 at 14:02 vote accept Ailiy Evan
Aug 16, 2021 at 13:57 comment added Ailiy Evan In fact, your answer for the second question is not clear. Why you see (19), you can conncet with $|B_t|$? How two explain (19)?
Aug 16, 2021 at 12:02 review First posts
Aug 16, 2021 at 14:44
Aug 16, 2021 at 11:56 history answered Kurt G. CC BY-SA 4.0