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Aug 11, 2021 at 13:37 vote accept Maximilian Janisch
Aug 10, 2021 at 18:07 answer added Maximilian Janisch timeline score: 1
Aug 10, 2021 at 18:05 comment added Maximilian Janisch @bathalf15320 Indeed I found what I needed (see my answer below).
Aug 10, 2021 at 15:00 comment added Maximilian Janisch @bathalf15320 Thank you so much! I'll try to update you on if I found what I needed in the near future.
Aug 9, 2021 at 15:00 comment added bathalf15320 jss100.campus.ciencias.ulisboa.pt where you will find the proceedings of a conference at Lisbon which include the article I referenced. I would recommend that you continue to publicações/textosdidacticos where you will find an accessible treatment to his approach to distributions, based on lectures he gave in Maryland.
Aug 9, 2021 at 14:49 comment added bathalf15320 Sebastião e Silva's articles are available at the site
Aug 9, 2021 at 14:48 comment added bathalf15320 Sebastão e silva's complete works are available at the site
Aug 9, 2021 at 8:16 comment added Maximilian Janisch @bathalf15320 I was not able to find the article (all I found is this page where you can demand Stanford library to scan it for you, but it seems that is only for Stanford students). Do you have a hint for me?
Aug 8, 2021 at 21:52 comment added Maximilian Janisch @bathalf15320 Thank you, I will look it up soon!
Aug 8, 2021 at 21:51 comment added Maximilian Janisch @mathworker21 ahh I apologize for getting a bit pissed then 😅
Aug 8, 2021 at 4:57 comment added bathalf15320 If the convolution of distributions $f$ and $g$ is defined, then so is that of $Df$ (distibutional derivative) and $g$ and the expected formula holds. This can be found in the article "Integrals and orders of growth of distributions" by J. Sebastião e Silva which can be found online and contains an elementary (freshman analysis level) treatment of distributions, their definite (partial) integrals and convolutions.
Aug 8, 2021 at 0:48 comment added mathworker21 @MaximilianJanisch nope, just an innocent question
Aug 7, 2021 at 23:39 comment added Maximilian Janisch (And I meant to write $\langle T',\phi\rangle = - \langle T, \phi'\rangle$.)
Aug 7, 2021 at 23:32 comment added Maximilian Janisch @mathworker21 (I do not know of a sensible way to define the convolution $T*f$ if $T$ is any tempered distribution and $f$ is any $L^2$-function.)
Aug 7, 2021 at 23:31 comment added Maximilian Janisch @mathworker21 Your question seems a bit supercilious, but that might be just me. In any case, the Definition that I am using is the following: If $T\in C^\infty_{\text c}(\mathbb R;\mathbb C)^*$, then $T'$ is the distribution given by $$\langle T',\phi\rangle = - \langle T,\phi\rangle.$$ If you have some great insight or if there is an elementary fact that I am missing that would allow me to use this in order to conclude that $$(\mathscr K * f)' = \mathscr K' * f,$$ I would be happy to hear it. Note that $f$ is in $L^2$, so a special property of $\mathscr K$ is used.
Aug 7, 2021 at 23:24 comment added Maximilian Janisch @ChristianRemling Thank you! I will check out the Coddington-Levinson book that you mentioned in the next days
Aug 7, 2021 at 22:00 comment added Christian Remling You still have the usual (existence and uniqueness) theory available also for ODEs in this more general interpretation; this is discussed in many books, for example Coddington-Levinson. Your formula is then the variation-of-constants formula for the solutions of an inhomogeneous linear ODE.
Aug 7, 2021 at 21:04 comment added mathworker21 do u know how $A'$ is defined?
Aug 7, 2021 at 18:52 history asked Maximilian Janisch CC BY-SA 4.0