Skip to main content
5 events
when toggle format what by license comment
Oct 2, 2020 at 12:42 comment added Sam Sanders My point is that the Hilbert-Bernays approach is definitely third-order. Previous systems (Hilbert-Ackermann) even involved higher types (than type 2/third-order). For whatever reason, even this is not a neutral statement to some, which is why I have asked the above question.
Oct 2, 2020 at 12:35 comment added Sam Sanders @AliEnayat Thanks for the suggestion. One of the shortcomings of that paper (in my personal opinion) is that the authors are trying to be too neutral: they are unwilling to just explicitly say that the Hilbert-Bernays system H involves third-order parameters defined via the epsilon operator. The weaker system K, meant to avoid the latter, still involves Feferman's mu. There is even a discussion about a version of countable choice in H and K, not provable in ZF given the third-order parameters. Finally, the system L can only be used to formalise math indirectly, according to H-B..
Oct 1, 2020 at 10:10 comment added none @Carl Mummert any idea?
Sep 28, 2020 at 18:22 comment added Ali Enayat The paper "Prehistory of the subsystems of second-order arithmetic" by Dean and Walsh presumably sheds light on your question. The paper was published in the Review of Symbolic Logic (2017), and a draft of it is also available via arxiv.org/abs/1612.06219
Sep 27, 2020 at 20:57 history asked Sam Sanders CC BY-SA 4.0