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Bounty Started worth 100 reputation by Tanya Vladi
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Bounty Started worth 50 reputation by Tanya Vladi
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Tanya Vladi
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Prove How to prove that $ \sum_{m=0}^{\infty} { \Gamma\{(1+2m)/\alpha\}\over \Gamma(1/2+m)} { (-t^2/4)^{m}\over m !} \ge (\alpha/2)^{3}\exp(-t^{2}/4) $

I would love to prove the following inequality
$$ {1\over \sqrt{\pi} } \sum_{m=0}^{\infty} \Gamma\{(1+2m)/\alpha\} { (-t^2)^{m}\over (2m) !}=$$ $$ \sum_{m=0}^{\infty} { \Gamma\{(1+2m)/\alpha\}\over \Gamma(1/2+m)} { (-t^2/4)^{m}\over m !} \ge (\alpha/2)^{3}\exp(-t^{2}/4) $$ $1<\alpha<2$, $t>0$, The question is connected to the other question I asked and got no answer for Prove $\int_{0}^{\infty} \cos(\omega x) \exp(-x^{\alpha}) \, {\rm d} x \ge {\alpha^2 \sqrt{\pi} \over 8} \exp \left( -\frac{\omega^2}{4} \right)$

Prove that $ \sum_{m=0}^{\infty} { \Gamma\{(1+2m)/\alpha\}\over \Gamma(1/2+m)} { (-t^2/4)^{m}\over m !} \ge (\alpha/2)^{3}\exp(-t^{2}/4) $

I would love to prove the following inequality
$$ {1\over \sqrt{\pi} } \sum_{m=0}^{\infty} \Gamma\{(1+2m)/\alpha\} { (-t^2)^{m}\over (2m) !}=$$ $$ \sum_{m=0}^{\infty} { \Gamma\{(1+2m)/\alpha\}\over \Gamma(1/2+m)} { (-t^2/4)^{m}\over m !} \ge (\alpha/2)^{3}\exp(-t^{2}/4) $$ $1<\alpha<2$, $t>0$

How to prove that $ \sum_{m=0}^{\infty} { \Gamma\{(1+2m)/\alpha\}\over \Gamma(1/2+m)} { (-t^2/4)^{m}\over m !} \ge (\alpha/2)^{3}\exp(-t^{2}/4) $

I would love to prove the following inequality
$$ {1\over \sqrt{\pi} } \sum_{m=0}^{\infty} \Gamma\{(1+2m)/\alpha\} { (-t^2)^{m}\over (2m) !}=$$ $$ \sum_{m=0}^{\infty} { \Gamma\{(1+2m)/\alpha\}\over \Gamma(1/2+m)} { (-t^2/4)^{m}\over m !} \ge (\alpha/2)^{3}\exp(-t^{2}/4) $$ $1<\alpha<2$, $t>0$, The question is connected to the other question I asked and got no answer for Prove $\int_{0}^{\infty} \cos(\omega x) \exp(-x^{\alpha}) \, {\rm d} x \ge {\alpha^2 \sqrt{\pi} \over 8} \exp \left( -\frac{\omega^2}{4} \right)$

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Tanya Vladi
  • 178
  • 2
  • 16

Prove that $ \sum_{m=0}^{\infty} { \Gamma\{(1+2m)/\alpha\}\over \Gamma(1/2+m)} { (-t^2/4)^{m}\over m !} \ge (\alpha/2)^{3}\exp(-t^{2}/4) $

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Tanya Vladi
  • 178
  • 2
  • 16

$ \sum_{m=0}^{\infty} { \Gamma\{(1+2m)/\alpha\}\over \Gamma(1/2+m)} { (-t^2/4)^{m}\over m !} \ge (\alpha/2)^{3}\exp(-t^{2}/4) $

I would love to prove the following inequality
$$ {1\over \sqrt{\pi} } \sum_{m=0}^{\infty} \Gamma\{(1+2m)/\alpha\} { (-t^2)^{m}\over (2m) !}=$$ $$ \sum_{m=0}^{\infty} { \Gamma\{(1+2m)/\alpha\}\over \Gamma(1/2+m)} { (-t^2/4)^{m}\over m !} \ge (\alpha/2)^{3}\exp(-t^{2}/4) $$ $1<\alpha<2$, $t>0$