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Lee
Lee
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Corrected title and added math mode
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edit approved Feb 16, 2020 at 20:16
RobPratt
edit approved Feb 16, 2020 at 20:16
RobPratt
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Does this equation have more than one integer solutionssolution?

Consider the following diophantine equation

n = (3^x - 2^x)÷(2^y $$n = (3^x - 2^x)/(2^y - 3^x),$$ where - 3^x). where x$x$ and y$y$ are positive integers and 2^y > 3^x$2^y > 3^x$.

Does n$n$ have any other integer solutions besides the case when x=1$x=1$ and y=2$y=2$, which give n=1$n=1$?

Does this equation have more than one integer solutions?

Consider the following diophantine equation

n = (3^x - 2^x)÷(2^y - 3^x). where x and y are positive integers and 2^y > 3^x.

Does n have any other integer solutions besides the case when x=1 and y=2 which give n=1?

Does this equation have more than one integer solution?

Consider the following diophantine equation $$n = (3^x - 2^x)/(2^y - 3^x),$$ where $x$ and $y$ are positive integers and $2^y > 3^x$.

Does $n$ have any other integer solutions besides the case when $x=1$ and $y=2$, which give $n=1$?

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Lee
Lee
  • 79
  • 1

Does this equation have more than one integer solutions?

Consider the following diophantine equation

n = (3^x - 2^x)÷(2^y - 3^x). where x and y are positive integers and 2^y > 3^x.

Does n have any other integer solutions besides the case when x=1 and y=2 which give n=1?