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Dec 10, 2019 at 4:05 comment added Dominic van der Zypen Thanks for your comments! If one of you can post their comment as an answer, we can close this thread
Dec 9, 2019 at 17:20 comment added Gabe Conant I assume the requirement $|V(H)|>1$ is to rule out choosing $H=K_1$ and $K=G$. But instead one could let $H=K_2$ and $K$ be the join $G+G$ of two disjoint copies of $G$.
Dec 9, 2019 at 15:57 comment added Gerhard Paseman Let H be a Cartesian product of G and K. I would think G would be a subgraph of the homomorphism graph. Gerhard "Turn Each Map Into Vertex" Paseman, 2019.12.09.
Dec 9, 2019 at 9:37 history asked Dominic van der Zypen CC BY-SA 4.0