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Nov 14, 2019 at 11:03 comment added Minseon Shin I believe it's called a "contracted product" in the literature.
Nov 14, 2019 at 9:17 comment added Angelo A commonly used notation, which avoids the confusion with fibered products, is $G \times^{P}Y$.
Nov 14, 2019 at 4:40 comment added Aaron Landesman $G \times_P Y$ is smooth because $G \times Y$ is a $P$-torsor over $G \times_P Y$. Then $G$ and $Y$ are both smooth, so $G \times Y$ is smooth. In general if $f: X \to Z$ is a smooth surjection then $X$ being smooth implies $Z$ is smooth. In fact, you only need that $f$ is fppf, though this fact is harder and the homological characterization of regularity. So smoothness of $G \times Y$ implies smoothness of $G \times_P Y$.
Nov 14, 2019 at 3:06 comment added Peter McNamara The notation is unfortunate because of the clash with the fibre product notation. Here one defines $G\times_PY=(G\times Y)/\sim$ where $(gp,y)\sim (g,py)$ for all $p\in P$.
Nov 14, 2019 at 0:15 history edited YCor CC BY-SA 4.0
added tag, specified "reductive" in title
Nov 14, 2019 at 0:05 history asked Xuqiang QIN CC BY-SA 4.0