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Oct 9, 2019 at 4:44 comment added Angelo No, they are not. See mathoverflow.net/questions/22015/…. And any case Wikipedia is not very authoritative.
Oct 9, 2019 at 1:21 comment added user30211 @Angelo I believe that is equivalent; see here en.wikipedia.org/wiki/….
Oct 8, 2019 at 17:30 comment added Angelo Formally smooth morphisms only have the property above with respect to nilpotent embeddings of affine schemes.
Oct 8, 2019 at 15:41 history asked user30211 CC BY-SA 4.0