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Aug 7, 2019 at 20:28 comment added Jochen Glueck @AnthonyQuas: Well, the argument in the quote certainly refers to what you write in your comment. Still, if one likes cones, one can also argue as follows: Given that the space of contiunous functions $C(K)$ on a compact space $K$ has a normal cone with non-empty interior, it follows, for every positive operator $T$ on $C(K)$, that the spectral radius of $T$ is an eigenvalue of the dual operator $T^*$.
Aug 7, 2019 at 19:47 comment added Anthony Quas I think there is no normal cone here, but instead compactness of the unit ball in the weak* topology (and continuity of $\mathcal L^*$ in that topology.
Aug 7, 2019 at 2:42 history asked Ilovemath CC BY-SA 4.0