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Jul 25, 2019 at 7:23 answer added Ayman Moussa timeline score: 3
Jun 27, 2019 at 15:33 vote accept Guy Fsone
Jun 27, 2019 at 15:16 comment added Hannes If $H^1(\Omega)$ is compactly embedded into $L^2(\Omega)$ in your setting, shouldn't the Vitali convergence theorem and tightness of the Lebesgue measure do the trick? (.. if you are fine with a subsequence ..)
Jun 27, 2019 at 15:04 answer added Aleksei Kulikov timeline score: 6
Jun 27, 2019 at 13:58 history asked Guy Fsone CC BY-SA 4.0