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Jun 10, 2019 at 21:08 comment added Yuval Peres Indeed there is no problem.
Jun 10, 2019 at 20:59 comment added Mateusz Kwaśnicki @YuvalPeres: Neither do I see a problem here: $f$ and $P$ do depend on a (fixed) $\varepsilon$. (But still it is far simpler to apply the Müntz–Szász theorem, as user131781 pointed out in their comment.)
Jun 10, 2019 at 19:53 comment added Yemon Choi @YuvalPeres I don't see a problem (perhaps I am being slow) - one fixes epsilon, defines $f=f_\epsilon$, and then chooses some $P$ that approximates $f_\epsilon$ to with $\epsilon$. What goes wrong?
Jun 10, 2019 at 13:18 comment added Yuval Peres How are you justifying the first step? The function $f$ you are approximating depends on $\epsilon$.
Jun 10, 2019 at 7:39 history undeleted Mateusz Kwaśnicki
Jun 10, 2019 at 7:39 history edited Mateusz Kwaśnicki CC BY-SA 4.0
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Jun 10, 2019 at 7:34 history deleted Mateusz Kwaśnicki via Vote
Jun 10, 2019 at 7:33 history answered Mateusz Kwaśnicki CC BY-SA 4.0