Skip to main content
added 116 characters in body
Source Link

The Cartan-Kuranishi theorem guarantees that a PDE or EDS can always be completed, by prolongation, to involution. My question is, and this is quite murky to gauge from the literature, whether Cartan's equivalence method (where prolongation and normalization of essential torsion is a little bit different from the standard prolongation of PDE and EDS) terminates at involution as an easy consequence of Cartan-Kuranishi for equivalence problems of constant type.

Some authors claim that this is so while others say that termination of Cartan's method has never really been proven, notably Bryant, Griffiths and Hsu in the introduction to the paper:

Toward a geometry of differential equations, Geometry, topology, & physics, 1–76, Conf. Proc. Lecture Notes Geom. Topology, IV, Int. Press, Cambridge, MA, 1995. Available from https://publications.ias.edu/node/262 (MR1358612)

EDIT: Clarified that I am talking about constant type equivalence problems.

The Cartan-Kuranishi theorem guarantees that a PDE or EDS can always be completed, by prolongation, to involution. My question is, and this is quite murky to gauge from the literature, whether Cartan's equivalence method (where prolongation and normalization of essential torsion is a little bit different from the standard prolongation of PDE and EDS) terminates at involution as an easy consequence of Cartan-Kuranishi.

Some authors claim that this is so while others say that termination of Cartan's method has never really been proven, notably Bryant, Griffiths and Hsu in the introduction to the paper:

Toward a geometry of differential equations, Geometry, topology, & physics, 1–76, Conf. Proc. Lecture Notes Geom. Topology, IV, Int. Press, Cambridge, MA, 1995. Available from https://publications.ias.edu/node/262 (MR1358612)

The Cartan-Kuranishi theorem guarantees that a PDE or EDS can always be completed, by prolongation, to involution. My question is, and this is quite murky to gauge from the literature, whether Cartan's equivalence method (where prolongation and normalization of essential torsion is a little bit different from the standard prolongation of PDE and EDS) terminates at involution as an easy consequence of Cartan-Kuranishi for equivalence problems of constant type.

Some authors claim that this is so while others say that termination of Cartan's method has never really been proven, notably Bryant, Griffiths and Hsu in the introduction to the paper:

Toward a geometry of differential equations, Geometry, topology, & physics, 1–76, Conf. Proc. Lecture Notes Geom. Topology, IV, Int. Press, Cambridge, MA, 1995. Available from https://publications.ias.edu/node/262 (MR1358612)

EDIT: Clarified that I am talking about constant type equivalence problems.

Gave bibliographic reference in case of link rot
Source Link
David Roberts
  • 35.5k
  • 11
  • 124
  • 349

The Cartan-Kuranishi theorem guarantees that a PDE or EDS can always be completed, by prolongation, to involution. My question is, and this is quite murky to gauge from the literature, whether Cartan's equivalence method (where prolongation and normalization of essential torsion is a little bit different from the standard prolongation of PDE and EDS) terminates at involution as an easy consequence of Cartan-Kuranishi.

Some authors claim that this is so while others say that termination of Cartan's method has never really been proven, notably Bryant, Griffiths and Hsu in the introduction to thisthe paper: https://publications.ias.edu/node/262

Toward a geometry of differential equations, Geometry, topology, & physics, 1–76, Conf. Proc. Lecture Notes Geom. Topology, IV, Int. Press, Cambridge, MA, 1995. Available from https://publications.ias.edu/node/262 (MR1358612)

The Cartan-Kuranishi theorem guarantees that a PDE or EDS can always be completed, by prolongation, to involution. My question is, and this is quite murky to gauge from the literature, whether Cartan's equivalence method (where prolongation and normalization of essential torsion is a little bit different from the standard prolongation of PDE and EDS) terminates at involution as an easy consequence of Cartan-Kuranishi.

Some authors claim that this is so while others say that termination of Cartan's method has never really been proven, notably Bryant, Griffiths and Hsu in the introduction to this paper: https://publications.ias.edu/node/262

The Cartan-Kuranishi theorem guarantees that a PDE or EDS can always be completed, by prolongation, to involution. My question is, and this is quite murky to gauge from the literature, whether Cartan's equivalence method (where prolongation and normalization of essential torsion is a little bit different from the standard prolongation of PDE and EDS) terminates at involution as an easy consequence of Cartan-Kuranishi.

Some authors claim that this is so while others say that termination of Cartan's method has never really been proven, notably Bryant, Griffiths and Hsu in the introduction to the paper:

Toward a geometry of differential equations, Geometry, topology, & physics, 1–76, Conf. Proc. Lecture Notes Geom. Topology, IV, Int. Press, Cambridge, MA, 1995. Available from https://publications.ias.edu/node/262 (MR1358612)

Source Link

Termination of Cartan's equivalence method

The Cartan-Kuranishi theorem guarantees that a PDE or EDS can always be completed, by prolongation, to involution. My question is, and this is quite murky to gauge from the literature, whether Cartan's equivalence method (where prolongation and normalization of essential torsion is a little bit different from the standard prolongation of PDE and EDS) terminates at involution as an easy consequence of Cartan-Kuranishi.

Some authors claim that this is so while others say that termination of Cartan's method has never really been proven, notably Bryant, Griffiths and Hsu in the introduction to this paper: https://publications.ias.edu/node/262