Timeline for Is it possible to prove unboundedness of 3rd order ODE?
Current License: CC BY-SA 4.0
15 events
when toggle format | what | by | license | comment | |
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S Jan 25, 2019 at 16:56 | history | suggested | user35202 |
numerical solution of ode
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Jan 25, 2019 at 16:55 | review | Suggested edits | |||
S Jan 25, 2019 at 16:56 | |||||
Jan 25, 2019 at 0:19 | vote | accept | user2175783 | ||
Jan 24, 2019 at 22:59 | answer | added | Robert Bryant | timeline score: 14 | |
Jan 24, 2019 at 14:57 | vote | accept | user2175783 | ||
Jan 25, 2019 at 0:19 | |||||
Jan 23, 2019 at 20:27 | answer | added | Robert Israel | timeline score: 3 | |
Jan 23, 2019 at 19:14 | comment | added | Robert Israel | There is always at least a one-parameter family of unbounded solutions, namely $x(t) = t^2/4 + c t + c^2 - A/2$. | |
Jan 23, 2019 at 19:14 | comment | added | user2175783 | @ChristianRemling Yes I mean all other solutions are unbounded for a certain range of $A$. It does seem like I am too optimistic making the claim about the integral diverging for $A\leq 0$ (the integrand will be positive for $A\leq 0$). I am thinking about it. | |
Jan 23, 2019 at 19:07 | history | edited | user2175783 | CC BY-SA 4.0 |
added 34 characters in body
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Jan 23, 2019 at 17:52 | comment | added | Christian Remling | Of course, $x=0$ is a bounded solution. Are you claiming that all other solutions are unbounded, or that there is at least one unbounded solution? I also don't understand how you conclude that the integral diverges when we don't have any information on the integrand. | |
Jan 23, 2019 at 16:54 | history | edited | user2175783 | CC BY-SA 4.0 |
edited title
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Jan 23, 2019 at 16:05 | comment | added | user2175783 | @YCor I welcome a better suggestion. Maybe "How to prove unboundness for a range of A?" | |
Jan 23, 2019 at 14:56 | history | edited | user2175783 | CC BY-SA 4.0 |
added 19 characters in body
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Jan 23, 2019 at 14:55 | review | First posts | |||
Jan 23, 2019 at 15:04 | |||||
Jan 23, 2019 at 14:51 | history | asked | user2175783 | CC BY-SA 4.0 |