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Post Closed as "Not suitable for this site" by Neil Strickland, abx, R.P., Stefan Waldmann, Dirk
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Dima Pasechnik
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Do you know the reference for this rawlaw?

I am graduate student.

As you know, the convolution operation satisfy the below equation due to commutative rawlaw. a(n)*b(n)*c(n) = a(n)*c(n)*b(n)

In addition, the muliplication operation also satisfy the below equation due to commutative rawlaw. a(n)b(n)c(n) = a(n)c(n)b(n)

however, to my knowledge, the below equation was not satisfied; a(n)b(n)*c(n) = a(n)*c(n)b(n)

Can I say that "the commutative rawlaw between multiplication operation and convolution operation does not satisfied" ?

FuthermoreFurthermore, do you know any reference for this phenomenon?

Best Regards,

Do you know the reference for this raw?

I am graduate student.

As you know, the convolution operation satisfy the below equation due to commutative raw. a(n)*b(n)*c(n) = a(n)*c(n)*b(n)

In addition, the muliplication operation also satisfy the below equation due to commutative raw. a(n)b(n)c(n) = a(n)c(n)b(n)

however, to my knowledge, the below equation was not satisfied; a(n)b(n)*c(n) = a(n)*c(n)b(n)

Can I say that "the commutative raw between multiplication operation and convolution operation does not satisfied" ?

Futhermore, do you know any reference for this phenomenon?

Best Regards,

Do you know the reference for this law?

I am graduate student.

As you know, the convolution operation satisfy the below equation due to commutative law. a(n)*b(n)*c(n) = a(n)*c(n)*b(n)

In addition, the muliplication operation also satisfy the below equation due to commutative law. a(n)b(n)c(n) = a(n)c(n)b(n)

however, to my knowledge, the below equation was not satisfied; a(n)b(n)*c(n) = a(n)*c(n)b(n)

Can I say that "the commutative law between multiplication operation and convolution operation does not satisfied" ?

Furthermore, do you know any reference for this phenomenon?

Source Link

Do you know the reference for this raw?

I am graduate student.

As you know, the convolution operation satisfy the below equation due to commutative raw. a(n)*b(n)*c(n) = a(n)*c(n)*b(n)

In addition, the muliplication operation also satisfy the below equation due to commutative raw. a(n)b(n)c(n) = a(n)c(n)b(n)

however, to my knowledge, the below equation was not satisfied; a(n)b(n)*c(n) = a(n)*c(n)b(n)

Can I say that "the commutative raw between multiplication operation and convolution operation does not satisfied" ?

Futhermore, do you know any reference for this phenomenon?

Best Regards,