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May 1, 2019 at 14:02 history bumped CommunityBot This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.
Jan 21, 2019 at 11:00 review Close votes
Feb 3, 2019 at 3:05
Jan 1, 2019 at 14:02 history bumped CommunityBot This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.
Dec 2, 2018 at 14:00 history bumped CommunityBot This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.
Nov 2, 2018 at 13:28 answer added Pierre PC timeline score: 0
Nov 2, 2018 at 12:50 comment added Taro Tokyo Firstly, $B_t-B_s - \frac{t-s}{1-s}(B_1-B_s) {\perp\!\!\!\perp} B_1-B_s $ (because they make a gaussian vector and their covariance is zero). Secondly, $B_t-B_s {\perp\!\!\!\perp} F_s$ ( markov property).
Nov 2, 2018 at 10:10 review First posts
Nov 2, 2018 at 11:29
Nov 2, 2018 at 10:00 history asked BKR CC BY-SA 4.0