Timeline for Can eigenvectors determine their original matrices given the basis of matrices space is small?
Current License: CC BY-SA 4.0
5 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Oct 25, 2018 at 13:18 | answer | added | Kapil | timeline score: 1 | |
| Oct 25, 2018 at 2:37 | comment | added | Sirui Lu | @RobertIsrael Is there any rigorous proof that the span of $A_1v$, $A_2 v$, $A_3v$ and $v$ will have dimension 3? | |
| Oct 25, 2018 at 2:15 | review | Close votes | |||
| Oct 29, 2018 at 11:02 | |||||
| Oct 25, 2018 at 1:54 | comment | added | Robert Israel | Of course it's not unique: you can multiply $(a_1, a_2, a_3, s)$ by the same scalar. Generically, that will be all, i.e. the span of $A_1 v$, $A_2 v$, $A_3 v$ and $v$ will have dimension $3$. | |
| Oct 25, 2018 at 1:26 | history | asked | Sirui Lu | CC BY-SA 4.0 |