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Luc Guyot
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Is the intersection of ramification groups in upper numbering of a p$p$-adic local field trivial?

Let $K$ be a p $p$-adic local field, for example $\mathbb{Q}_p$. Let G$G$ be the absolute Galois group of $K$, and let $G^v$($v\ge -1$) be the ramification groups in upper numbering, then is it turetrue that $\bigcap_{v=0}^\infty G^v=\{0\}$?

Is the intersection of ramification groups in upper numbering of a p-adic local field trivial?

Let $K$ be a p-adic local field, for example $\mathbb{Q}_p$. Let G be the absolute Galois group of $K$, and let $G^v$($v\ge -1$) be the ramification groups in upper numbering, then is it ture that $\bigcap_{v=0}^\infty G^v=\{0\}$?

Is the intersection of ramification groups in upper numbering of a $p$-adic local field trivial?

Let $K$ be a $p$-adic local field, for example $\mathbb{Q}_p$. Let $G$ be the absolute Galois group of $K$, and let $G^v$($v\ge -1$) be the ramification groups in upper numbering, then is it true that $\bigcap_{v=0}^\infty G^v=\{0\}$?

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Bonbon
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Let $K$ be a p p-adic local field, for example $\mathbb{Q}_p$. Let G be the absolute Galois group of $K$, and let $G^v$($v\ge -1$) be the ramification groups in upper numbering, then is it ture that $\bigcap_{v=0}^\infty G^v=\{0\}$?

Let $K$ be a p-adic local field, for example $\mathbb{Q}_p$. Let G be the absolute Galois group of $K$, and let $G^v$($v\ge -1$) be the ramification groups in upper numbering, then is it ture that $\bigcap_{v=0}^\infty G^v=\{0\}$?

Let $K$ be a p-adic local field, for example $\mathbb{Q}_p$. Let G be the absolute Galois group of $K$, and let $G^v$($v\ge -1$) be the ramification groups in upper numbering, then is it ture that $\bigcap_{v=0}^\infty G^v=\{0\}$?

Source Link
Bonbon
  • 806
  • 4
  • 14

Is the intersection of ramification groups in upper numbering of a p-adic local field trivial?

Let $K$ be a p-adic local field, for example $\mathbb{Q}_p$. Let G be the absolute Galois group of $K$, and let $G^v$($v\ge -1$) be the ramification groups in upper numbering, then is it ture that $\bigcap_{v=0}^\infty G^v=\{0\}$?