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Mar 23, 2018 at 12:30 history edited Sean Lawton CC BY-SA 3.0
deleted 45 characters in body
Mar 15, 2018 at 14:10 comment added Qfwfq (Just deleted my answer: I didn't read carefully: you're looking for affine varieties that are affinely paved)
Mar 14, 2018 at 23:43 vote accept Sean Lawton
Mar 14, 2018 at 22:45 answer added David E Speyer timeline score: 16
Mar 14, 2018 at 22:38 comment added David E Speyer @dhy This is wrong. That shows that $\mathbb{A}^n$ can not be a principal open, but it can be the complement of a nonprincipal hypersurface. I'll put up an example shortly.
Mar 14, 2018 at 21:44 comment added dhy Any affine variety containing $\mathbb{A}^n$ as an open subset must be $\mathbb{A}^n$ itself. An affine open embedding corresponds to a localization at the level of rings, but there are no non-constant invertible functions in $k[x_1,\cdots,x_n]$.
Mar 14, 2018 at 21:22 comment added YCor what do you call "non-trivial"?
Mar 14, 2018 at 21:08 history asked Sean Lawton CC BY-SA 3.0