Let $V$ be an algebraic variety. If there is a finite ascending chain of Zariski closed sets $\emptyset=V_0\subset V_1\subset \cdots \subset V_n=V$ such that $V_i-V_{i-1}$ is a fintie disjoint union of copies of affine space $\mathbb{A}^i$ we say $V$ is *affine paved* (so $V$ is "algebraically cellular").

Note: there are non-equivalent variations of this definition (see here).

One can deduce that an affine paved variety (over $\mathbb{C}$) has no odd cohomology and its even cohomology is free abelian.

Examples:

- Finite disjoint unions of affine space are affine paved. Let's call these examples "trivial."
- Projective space is affine paved.
- The Bruhat cells in a flag variety show there are interesting projective examples.

Question: Are there non-trivial affine paved affine varieties?

This very well might be a silly question. Perhaps the affine cone over an affine paved projective variety always works? It doesn't seem clear to me, and I figured someone out there might have thought about such examples before (Google doesn't seem to know any).

affinevarieties that are affinely paved) $\endgroup$ – Qfwfq Mar 15 '18 at 14:10