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Feb 28, 2018 at 10:43 comment added YCor A natural extension of the definition is to fix a field extension $k_0\to k$ and to say that $k$ is "unrepeatable" over $k_0$ if for every extension $k_0\to L$ there is at most one $k_0$-embedding $k\to L$. Then when $k_0$ is perfect, $k$ unrepeatable forces $k=k_0$. More generally this holds iff $k$ is a purely inseparable extension of $k_0$ (in the sense that $k$ belongs to the smallest perfect extension of $k_0$). I think this generality better emphasizes what happens (in the answer to the original question, prime fields being perfect, the role of perfectness doesn't show up explicitly).
Feb 28, 2018 at 6:38 vote accept Omar Antolín-Camarena
Feb 28, 2018 at 5:42 answer added Sándor Kovács timeline score: 15
Feb 28, 2018 at 5:21 comment added Omar Antolín-Camarena I definitely should have mentioned that, @GregMartin. (Minor correction: Frobenius endomorphism: it isn't always surjective. It's existence and non-identity-ness still shows unrepeatable positive characteristic fields are prime as you said.)
Feb 28, 2018 at 5:03 comment added Greg Martin Non-prime finite fields are not unrepeatable, since the Frobenius $x\mapsto x^p$ gives a nontrivial automorphism of every $\Bbb F_{p^k}$ with $k\ge2$. Indeed, I believe this shows that no non-prime field of positive characteristic is unrepeatable.
Feb 28, 2018 at 4:59 history edited Greg Martin CC BY-SA 3.0
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Feb 28, 2018 at 4:55 history asked Omar Antolín-Camarena CC BY-SA 3.0