I propose the following problem (Maybe it has a trivial solution):
Let $n$ be a positive integer such that $$n=1 \mod 4$$$$n\equiv1 \pmod 4.$$
Then the problem is about findingto find a rational $x$ inas a function of $n$ such that $ \dfrac{3n+3x+n^{2}}{12}$ and $\dfrac{n(n+3)(3n+3x+n^{2})}{36x}$ are $$ \dfrac{3n+3x+n^{2}}{12} \quad\text{and}\quad \dfrac{n(n+3)(3n+3x+n^{2})}{36x}$$ are both strictelystrictly positive integers. Or at least how one can proves that such a $x$ exists.