Skip to main content
9 events
when toggle format what by license comment
S Dec 8, 2017 at 22:57 history suggested j0equ1nn CC BY-SA 3.0
the real answer was in the comments do I summarized them in the answer
Dec 8, 2017 at 19:10 review Suggested edits
S Dec 8, 2017 at 22:57
Dec 7, 2017 at 23:08 vote accept j0equ1nn
Dec 7, 2017 at 23:08 comment added j0equ1nn Ah okay, I see what you mean. Thanks.
Dec 7, 2017 at 22:27 comment added Igor Rivin It's in the link in my answer.
Dec 7, 2017 at 21:59 comment added j0equ1nn That makes sense, but let's say I give you a specific matrix. Can we say exactly what the pair of light like vectors are? I have not found any literature on a conformal map from $\overline{\mathcal{H}^3}$ to $\mathcal{I}^3\cup\big(\big\{p\in\mathbb{R}^{3,1}\mid\mathrm{n}(p)=0\big\}/\sim\big)$.
Dec 7, 2017 at 21:34 comment added Igor Rivin @j0equ1nn The two endpoints you mention in the OP give two (light-like) vectors. Their span is your geodesic.
Dec 7, 2017 at 20:39 comment added j0equ1nn That works fine for points but is awkward to do on an entire geodesic in the upper half-plane. I'm looking for a way of characterizing the plane in $\mathbb{R}^4$ that intersects with $\mathcal{I}^3$ to give $g$. Since this depends only on the matrix entries, there should be some function $\mathrm{PSL}(2,\mathbb{C})\rightarrow\mathbb{R}^4\times\mathbb{R}^4$ that outputs this pair of vectors.
Dec 7, 2017 at 18:59 history answered Igor Rivin CC BY-SA 3.0