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Kim Morrison
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Say f: X → Y is a morphism of schemes. The sheaf direct image functor f always has a left adjoint, namely the sheaf inverse image functor f (with tensoring).

Under what (sufficient) conditions do we know that f has a right adjoint? What is it?

EditAnswer to a related question (edit): What I'm looking for are appropriately general sufficient conditions... Certainly exactness ofIf f ispreserves quasicoherence, then its restriction to quasicoherents f: QCoh(X) → QCoh(Y) has a right adjoint when f is necessaryaffine condition(in particular, any closed immersion or finite morphism will do). As well The basic idea is to globalize the affine case (see Eric Wofsey's answer below); thanks to Pablo Solis for pointing me to page 6 of Ravi Vakil's notes explaining this.

In this question, perhaps I should be clear that I'm not assuming quasi-coherencenot in theserestricting to the quasi-coherent categories of O. One reason for working with non-quasicoherents is that jX!-Modules , the "extension by zero" right adjoint to j for an open immersion j, doesn't take qcoh to qcoh.

Say f: X → Y is a morphism of schemes. The sheaf direct image functor f always has a left adjoint, namely the sheaf inverse image functor f (with tensoring).

Under what conditions do we know that f has a right adjoint? What is it?

Edit: What I'm looking for are appropriately general sufficient conditions... Certainly exactness of f is a necessary condition. As well, perhaps I should be clear that I'm not assuming quasi-coherence in these categories of OX-Modules

Say f: X → Y is a morphism of schemes. The sheaf direct image functor f always has a left adjoint, namely the sheaf inverse image functor f (with tensoring).

Under what (sufficient) conditions do we know that f has a right adjoint? What is it?

Answer to a related question (edit): If f preserves quasicoherence, then its restriction to quasicoherents f: QCoh(X) → QCoh(Y) has a right adjoint when f is affine (in particular, any closed immersion or finite morphism will do). The basic idea is to globalize the affine case (see Eric Wofsey's answer below); thanks to Pablo Solis for pointing me to page 6 of Ravi Vakil's notes explaining this.

In this question, I'm not restricting to the quasi-coherent categories. One reason for working with non-quasicoherents is that j! , the "extension by zero" right adjoint to j for an open immersion j, doesn't take qcoh to qcoh.

clarification/emphasis; deleted 21 characters in body
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Andrew Critch
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Say f: X → Y is a morphism of schemes. The sheaf direct image functor f always has a left adjoint, namely the sheaf inverse image functor f (with tensoring).

Under what conditions do we know that f has a right adjoint? What is it?

Edit: What I'm looking for are appropriately general sufficient conditions... Certainly exactness of f is a necessary condition. As well, perhaps I should be clear that I'm not assuming quasi-coherence in these categories of OX-Modules

Say f: X → Y is a morphism of schemes. The sheaf direct image functor f always has a left adjoint, namely the sheaf inverse image functor f (with tensoring).

Under what conditions do we know that f has a right adjoint? What is it?

Say f: X → Y is a morphism of schemes. The sheaf direct image functor f always has a left adjoint, namely the sheaf inverse image functor f (with tensoring).

Under what conditions do we know that f has a right adjoint? What is it?

Edit: What I'm looking for are appropriately general sufficient conditions... Certainly exactness of f is a necessary condition. As well, perhaps I should be clear that I'm not assuming quasi-coherence in these categories of OX-Modules

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Ilya Nikokoshev
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