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Myshkin
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K-theory of an elliptic curve.

Given an elliptic curve $E$ over $\mathbb{Q}$, I have read somewhere (But I can't remember exactly where) that the Beilinson conjecture asserts that: The rank of the albelian group $K_{2}(E)$ (the second algebraic K-theory  ) is equal to the rank of the abelian group of the rational points $E(\mathbb{Q})$.

conjectureConjecture: $\textrm{rk } K_{2}(E)= \textrm{rk } E(\mathbb{Q})$

Question What are some evidences of such conjecture  ? Is it verified in some known cases  ?

K-theory of an elliptic curve.

Given an elliptic curve $E$ over $\mathbb{Q}$, I have read somewhere (But I can't remember exactly where) that the Beilinson conjecture asserts that: The rank of the albelian group $K_{2}(E)$ (the second algebraic K-theory  ) is equal to the rank of the abelian group of the rational points $E(\mathbb{Q})$.

conjecture: $\textrm{rk } K_{2}(E)= \textrm{rk } E(\mathbb{Q})$

Question What are some evidences of such conjecture  ? Is it verified in some known cases  ?

K-theory of an elliptic curve

Given an elliptic curve $E$ over $\mathbb{Q}$, I have read somewhere (But I can't remember exactly where) that the Beilinson conjecture asserts that: The rank of the albelian group $K_{2}(E)$ (the second algebraic K-theory) is equal to the rank of the abelian group of the rational points $E(\mathbb{Q})$.

Conjecture: $\textrm{rk } K_{2}(E)= \textrm{rk } E(\mathbb{Q})$

Question What are some evidences of such conjecture? Is it verified in some known cases?

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symmetry
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K-theory of an elliptic curve.

Given an elliptic curve $E$ over $\mathbb{Q}$, I have read somewhere (But I can't remember exactly where) that the Beilinson conjecture asserts that: The rank of the albelian group $K_{2}(E)$ (the second algebraic K-theory ) is equal to the rank of the abelian group of the rational points $E(\mathbb{Q})$.

conjecture: $\textrm{rk } K_{2}(E)= \textrm{rk } E(\mathbb{Q})$

Question What are some evidences of such conjecture ? Is it verified in some known cases ?