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Jun 11, 2017 at 9:56 comment added Severin Schraven @reuns I'm sorry, I don't see, how I can use the Fourier transform to get an approximation in the supremum-norm. Could you tell me, how you would proceed?
Jun 11, 2017 at 9:35 comment added reuns I would say $\displaystyle\mathcal{M}(f)= \left\{ \nu\in \mathbb{R}: \exists k \in \mathbb{N}, \lim_{t\rightarrow \infty} \frac{1}{t} \int_0^t (f(x))^ke^{-i\nu x}dx\neq 0 \right\} $ which is a $\mathbb{Z}$-module, and I would look at the Fourier transform of $f$ in the sense of distributions
Jun 5, 2017 at 12:53 vote accept Severin Schraven
Jun 5, 2017 at 12:43 answer added Francois Ziegler timeline score: 3
Jun 5, 2017 at 11:38 history edited Severin Schraven CC BY-SA 3.0
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Jun 5, 2017 at 9:16 history edited Severin Schraven CC BY-SA 3.0
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Jun 5, 2017 at 9:01 history asked Severin Schraven CC BY-SA 3.0