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Fedor Petrov
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Purely algebraic proof. We induct on $n$ and fix. Fix $\pi_n$. This part of athe sum equals $z_{\pi_n}/(z_1+\dots+z_n)$ by induction proposition. Now sum up by all values of $\pi_n$.

Purely algebraic proof. We induct on $n$ and fix $\pi_n$. This part of a sum equals $z_{\pi_n}/(z_1+\dots+z_n)$ by induction proposition. Now sum up by all values of $\pi_n$.

Purely algebraic proof. We induct on $n$. Fix $\pi_n$. This part of the sum equals $z_{\pi_n}/(z_1+\dots+z_n)$ by induction proposition. Now sum up by all values of $\pi_n$.

Source Link
Fedor Petrov
  • 108.8k
  • 9
  • 264
  • 459

Purely algebraic proof. We induct on $n$ and fix $\pi_n$. This part of a sum equals $z_{\pi_n}/(z_1+\dots+z_n)$ by induction proposition. Now sum up by all values of $\pi_n$.