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Dec 5, 2016 at 21:09 vote accept Saal Hardali
Dec 5, 2016 at 21:03 answer added Will Sawin timeline score: 9
Dec 5, 2016 at 20:55 history edited Saal Hardali CC BY-SA 3.0
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Dec 5, 2016 at 20:49 history edited Saal Hardali CC BY-SA 3.0
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Dec 5, 2016 at 20:48 comment added Will Sawin For either of these to be true, there must be an action of $G$ on $k(X)$. But $G$ acts on $\tilde{k(X)}$, which is usually not equal to $k(X)$.
Dec 5, 2016 at 20:48 history edited Saal Hardali CC BY-SA 3.0
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Dec 5, 2016 at 20:46 comment added Will Sawin Mohan means that your statements "Generically such an action always exists" and "If $X$ and $Y$ are curves then I think this is always the case" both seem wrong unless you are using a different definition of one of the terms than usual.
Dec 5, 2016 at 20:40 comment added Saal Hardali @Mohan What do you mean?
Dec 5, 2016 at 20:38 comment added Mohan How did you come to conclude 1? This situation can not be better than Galois theory for filed extensions.
Dec 5, 2016 at 20:35 history edited Saal Hardali CC BY-SA 3.0
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Dec 5, 2016 at 20:20 history asked Saal Hardali CC BY-SA 3.0