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SashaP
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bijection Bijection of critical points on two manifolds

Suppose that f$f$ and g$g$ are two smooth functions defined on $R^n$. Assume that $(a-\epsilon, b+\epsilon)$ contains no critical point of g$g$. Then $g^{-1}[a,b]$ it homomorphic to $g^{-1}(a)\times [a,b]$. Now we consider the critical points of the function f$f$ restricted on $g=c$, $f|_{g=c}$, $c\in [a,b]$. My aim is to show that there is a bijection between critical points of $f|_{g=a}$ and $f|_{g=b}$. 

There are counterexamples to my guess. For example, f,g $R^2\to R$$f,g:\mathbb{R}^2\to \mathbb{R}$, $f(x,y)=x^3-xy$, $g(x,y)=y$. Then g$g$ has no critical points, $f|_{g=1}$ has two critical points, but $f|_{g=0}$ has one critical pointspoint, and $f|_{g=-1}$ has no critical points. Maybe under

Maybe some conditions of fon $f$ would be enough, like f$f$ also has no critical points. Is there a theorem on this?

bijection of critical points on two manifolds

Suppose that f and g are two smooth functions defined on $R^n$. Assume that $(a-\epsilon, b+\epsilon)$ contains no critical point of g. Then $g^{-1}[a,b]$ it homomorphic to $g^{-1}(a)\times [a,b]$. Now we consider the critical points of the function f restricted on $g=c$, $f|_{g=c}$, $c\in [a,b]$. My aim is to show that there is a bijection between critical points of $f|_{g=a}$ and $f|_{g=b}$. There are counterexamples to my guess. For example, f,g $R^2\to R$, $f(x,y)=x^3-xy$, $g(x,y)=y$. Then g has no critical points, $f|_{g=1}$ has two critical points, but $f|_{g=0}$ has one critical points, and $f|_{g=-1}$ has no critical points. Maybe under some conditions of f would be enough, like f also has no critical points. Is there a theorem on this?

Bijection of critical points on two manifolds

Suppose that $f$ and $g$ are two smooth functions defined on $R^n$. Assume that $(a-\epsilon, b+\epsilon)$ contains no critical point of $g$. Then $g^{-1}[a,b]$ it homomorphic to $g^{-1}(a)\times [a,b]$. Now we consider the critical points of the function $f$ restricted on $g=c$, $f|_{g=c}$, $c\in [a,b]$. My aim is to show that there is a bijection between critical points of $f|_{g=a}$ and $f|_{g=b}$. 

There are counterexamples to my guess. For example, $f,g:\mathbb{R}^2\to \mathbb{R}$, $f(x,y)=x^3-xy$, $g(x,y)=y$. Then $g$ has no critical points, $f|_{g=1}$ has two critical points, but $f|_{g=0}$ has one critical point, and $f|_{g=-1}$ has no critical points.

Maybe some conditions on $f$ would be enough, like $f$ also has no critical points. Is there a theorem on this?

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bijection of critical points on two manifolds

Suppose that f and g are two smooth functions defined on $R^n$. Assume that $(a-\epsilon, b+\epsilon)$ contains no critical point of g. Then $g^{-1}[a,b]$ it homomorphic to $g^{-1}(a)\times [a,b]$. Now we consider the critical points of the function f restricted on $g=c$, $f|_{g=c}$, $c\in [a,b]$. My aim is to show that there is a bijection between critical points of $f|_{g=a}$ and $f|_{g=b}$. There are counterexamples to my guess. For example, f,g $R^2\to R$, $f(x,y)=x^3-xy$, $g(x,y)=y$. Then g has no critical points, $f|_{g=1}$ has two critical points, but $f|_{g=0}$ has one critical points, and $f|_{g=-1}$ has no critical points. Maybe under some conditions of f would be enough, like f also has no critical points. Is there a theorem on this?