Timeline for Why is the semisimple rank of a connected reductive group equal to the rank of the commutator?
Current License: CC BY-SA 3.0
6 events
| when toggle format | what | by | license | comment | |
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| Sep 6, 2019 at 9:02 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
| Aug 7, 2019 at 8:02 | answer | added | D_S | timeline score: 5 | |
| Oct 25, 2016 at 23:03 | review | Close votes | |||
| Oct 27, 2016 at 8:21 | |||||
| Oct 25, 2016 at 22:43 | comment | added | YCor | Yes, the rank is additive under exact sequences, and it's easier when the kernel in the exact sequence is finite. Anyway, this is an exercise. | |
| Oct 25, 2016 at 22:42 | comment | added | YCor | "So it's a quotient by a finite...": you're assuming there that $G$ is reductive. | |
| Oct 25, 2016 at 22:02 | history | asked | Not a grad student | CC BY-SA 3.0 |