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Todd Trimble
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This is a question about generalizations of the twin primes conjecture.

I would likelike to know a counterexample, or a proofproof, forfor the following cpuple orfollowing couple of related arithmeticalarithmetical sentences:. The first is

$(\forall p)(\exists n)(\exists q)( Prime(p) \wedge Prime (q) \wedge (p = 2^n + q))$$(\forall p) Prime(p) \Rightarrow (\exists n)(\exists q)(Prime (q) \wedge (p = 2^n + q))$

In informal wordsMore informally, everyif $p$ is prime number, then $p$ cancan be written aswritten as the sum of a smaller primeprime $q$ and a power of twoa power of $2$. The second is

$(\forall q)(\exists n)(\exists p) ( Prime(p) \wedge Prime (q) \wedge (p = 2^n + q))$$(\forall q) Prime(q) \Rightarrow (\exists n)(\exists p) (Prime(p) \wedge (p = 2^n + q))$

In informal wordsMore informally, for every prime numberif $q$ thereis prime, then there exists a number  $n$ such that the sum of $q$ and the $n$-th power of twoof $2$ is a prime number.

This is a question about generalizations of the twin primes conjecture.

I would like to know a counterexample, or a proof, for the following cpuple or related arithmetical sentences:

$(\forall p)(\exists n)(\exists q)( Prime(p) \wedge Prime (q) \wedge (p = 2^n + q))$

In informal words, every prime number $p$ can be written as the sum of a smaller prime $q$ and a power of two.

$(\forall q)(\exists n)(\exists p) ( Prime(p) \wedge Prime (q) \wedge (p = 2^n + q))$

In informal words, for every prime number $q$ there exists a number  $n$ such that the sum of $q$ and the $n$-th power of two is a prime number.

This is a question about generalizations of the twin primes conjecture.

I would like to know a counterexample, or a proof, for the following couple of related arithmetical sentences. The first is

$(\forall p) Prime(p) \Rightarrow (\exists n)(\exists q)(Prime (q) \wedge (p = 2^n + q))$

More informally, if $p$ is prime, then $p$ can be written as the sum of a smaller prime $q$ and a power of $2$. The second is

$(\forall q) Prime(q) \Rightarrow (\exists n)(\exists p) (Prime(p) \wedge (p = 2^n + q))$

More informally, if $q$ is prime, then there exists a number $n$ such that the sum of $q$ and the $n$-th power of $2$ is a prime number.

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YCor
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This question in principle can be answered Generalizations of the twin primes conjecture

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This question in principle can be answered

This is a question about generalizations of the twin primes conjecture.

I would like to know a counterexample, or a proof, for the following cpuple or related arithmetical sentences:

$(\forall p)(\exists n)(\exists q)( Prime(p) \wedge Prime (q) \wedge (p = 2^n + q))$

In informal words, every prime number $p$ can be written as the sum of a smaller prime $q$ and a power of two.

$(\forall q)(\exists n)(\exists p) ( Prime(p) \wedge Prime (q) \wedge (p = 2^n + q))$

In informal words, for every prime number $q$ there exists a number $n$ such that the sum of $q$ and the $n$-th power of two is a prime number.