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Oct 18, 2016 at 2:09 comment added YCor You're both right (it's natural in the setting of oriented manifolds, rather than besides naturality...)
Oct 17, 2016 at 22:32 review Close votes
Oct 18, 2016 at 8:26
Oct 17, 2016 at 22:17 comment added HeinrichD Besides naturality, we also need that $g^*[X]=[X]$ for $g \in G$, which is because $G$ acts by orientation-preserving automorphisms.
Oct 17, 2016 at 22:16 comment added Alex Degtyarev Because all products are natural?
Oct 17, 2016 at 22:13 history asked Stanley Chang CC BY-SA 3.0