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Schur multiplier of $Sp(2g, \mathbb{Z}_2/2)$ for $g \geq 3$

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This question is about the computation of $H_2(Sp(2g, \mathbb{Z}_2), \mathbb{Z})$$H_2(Sp(2g, \mathbb{Z}/2), \mathbb{Z})$, where $Sp(2g, \mathbb{Z}_2)$$Sp(2g, \mathbb{Z}/2)$ is the group of symplectic $2g \times 2g$ matrices over $\mathbb{Z}_2$$\mathbb{Z}/2$. With respect to this computation I have seen quotations to the following two papers:

According to the quotations of Stein's and Steinberg's papers the result is that $H_2(Sp(2g, \mathbb{Z}_2), \mathbb{Z}) = 0$$H_2(Sp(2g, \mathbb{Z}/2), \mathbb{Z}) = 0$ for $g \geq 3$.

My two concerns are:

  1. The papers by Stein and Steinberg do not directly give the computation of $H_2(Sp(2g, \mathbb{Z}_2), \mathbb{Z})$$H_2(Sp(2g, \mathbb{Z}/2), \mathbb{Z})$. So my first question is if it is really possible to extract this result from these papers?

  2. There is a discrepancy in the case $g=3$ between the quotations of Stein's and Steinberg's papers - which say that $H_2(Sp(6, \mathbb{Z}_2), \mathbb{Z}) =0$$H_2(Sp(6, \mathbb{Z}/2), \mathbb{Z}) =0$ - and the computation of this group done with GAP (the computational system for discrete algebra). GAP gives $H_2(Sp(6, \mathbb{Z}_2), \mathbb{Z}) = \mathbb{Z}_2$$H_2(Sp(6, \mathbb{Z}/2), \mathbb{Z}) = \mathbb{Z}/2$. Checking on GAP, the process that the computer goes through to get the computation looks correct. Is there an error in Stein's and/or Steinberg's paper or is it a misinterpretation of the case $g=3$ in the quotation?

This question is about the computation of $H_2(Sp(2g, \mathbb{Z}_2), \mathbb{Z})$, where $Sp(2g, \mathbb{Z}_2)$ is the group of symplectic $2g \times 2g$ matrices over $\mathbb{Z}_2$. With respect to this computation I have seen quotations to the following two papers:

According to the quotations of Stein's and Steinberg's papers the result is that $H_2(Sp(2g, \mathbb{Z}_2), \mathbb{Z}) = 0$ for $g \geq 3$.

My two concerns are:

  1. The papers by Stein and Steinberg do not directly give the computation of $H_2(Sp(2g, \mathbb{Z}_2), \mathbb{Z})$. So my first question is if it is really possible to extract this result from these papers?

  2. There is a discrepancy in the case $g=3$ between the quotations of Stein's and Steinberg's papers - which say that $H_2(Sp(6, \mathbb{Z}_2), \mathbb{Z}) =0$ - and the computation of this group done with GAP (the computational system for discrete algebra). GAP gives $H_2(Sp(6, \mathbb{Z}_2), \mathbb{Z}) = \mathbb{Z}_2$. Checking on GAP, the process that the computer goes through to get the computation looks correct. Is there an error in Stein's and/or Steinberg's paper or is it a misinterpretation of the case $g=3$ in the quotation?

This question is about the computation of $H_2(Sp(2g, \mathbb{Z}/2), \mathbb{Z})$, where $Sp(2g, \mathbb{Z}/2)$ is the group of symplectic $2g \times 2g$ matrices over $\mathbb{Z}/2$. With respect to this computation I have seen quotations to the following two papers:

According to the quotations of Stein's and Steinberg's papers the result is that $H_2(Sp(2g, \mathbb{Z}/2), \mathbb{Z}) = 0$ for $g \geq 3$.

My two concerns are:

  1. The papers by Stein and Steinberg do not directly give the computation of $H_2(Sp(2g, \mathbb{Z}/2), \mathbb{Z})$. So my first question is if it is really possible to extract this result from these papers?

  2. There is a discrepancy in the case $g=3$ between the quotations of Stein's and Steinberg's papers - which say that $H_2(Sp(6, \mathbb{Z}/2), \mathbb{Z}) =0$ - and the computation of this group done with GAP (the computational system for discrete algebra). GAP gives $H_2(Sp(6, \mathbb{Z}/2), \mathbb{Z}) = \mathbb{Z}/2$. Checking on GAP, the process that the computer goes through to get the computation looks correct. Is there an error in Stein's and/or Steinberg's paper or is it a misinterpretation of the case $g=3$ in the quotation?

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Schur multiplier of $Sp(2g, \mathbb{Z}_2)$ for $g \geq 3$

This question is about the computation of $H_2(Sp(2g, \mathbb{Z}_2), \mathbb{Z})$, where $Sp(2g, \mathbb{Z}_2)$ is the group of symplectic $2g \times 2g$ matrices over $\mathbb{Z}_2$. With respect to this computation I have seen quotations to the following two papers:

According to the quotations of Stein's and Steinberg's papers the result is that $H_2(Sp(2g, \mathbb{Z}_2), \mathbb{Z}) = 0$ for $g \geq 3$.

My two concerns are:

  1. The papers by Stein and Steinberg do not directly give the computation of $H_2(Sp(2g, \mathbb{Z}_2), \mathbb{Z})$. So my first question is if it is really possible to extract this result from these papers?

  2. There is a discrepancy in the case $g=3$ between the quotations of Stein's and Steinberg's papers - which say that $H_2(Sp(6, \mathbb{Z}_2), \mathbb{Z}) =0$ - and the computation of this group done with GAP (the computational system for discrete algebra). GAP gives $H_2(Sp(6, \mathbb{Z}_2), \mathbb{Z}) = \mathbb{Z}_2$. Checking on GAP, the process that the computer goes through to get the computation looks correct. Is there an error in Stein's and/or Steinberg's paper or is it a misinterpretation of the case $g=3$ in the quotation?