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Post Closed as "Not suitable for this site" by Andrés E. Caicedo, Joonas Ilmavirta, Alex Degtyarev, Stefan Kohl, András Bátkai
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is exist such Is it possible that $(a,b,c)$, $(x,y,a)$, $(p,q,b)$ are a Pythagorean tripletriples simultaneously?

IsDo there exist postive integer integers $a,b,c,x,y,p,q$ such $(a,b,c)$,such $(a,b,c),(x,y,a),(p,q,b)$$(x,y,a)$, $(p,q,b)$ are aall Pythagorean tripletriples?

I.e That is, does the system $$\begin{cases} a^2+b^2=c^2\\ x^2+y^2=a^2\\ p^2+q^2=b^2 \end{cases}$$ have a postive integersinteger solution?

is exist such $(a,b,c),(x,y,a),(p,q,b)$ are a Pythagorean triple?

Is there exist postive integer $a,b,c,x,y,p,q$,such $(a,b,c),(x,y,a),(p,q,b)$ are a Pythagorean triple?

I.e $$\begin{cases} a^2+b^2=c^2\\ x^2+y^2=a^2\\ p^2+q^2=b^2 \end{cases}$$ have postive integers solution?

Is it possible that $(a,b,c)$, $(x,y,a)$, $(p,q,b)$ are Pythagorean triples simultaneously?

Do there exist postive integers $a,b,c,x,y,p,q$ such $(a,b,c)$, $(x,y,a)$, $(p,q,b)$ are all Pythagorean triples? That is, does the system $$\begin{cases} a^2+b^2=c^2\\ x^2+y^2=a^2\\ p^2+q^2=b^2 \end{cases}$$ have a postive integer solution?

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is exist such $(a,b,c),(x,y,a),(p,q,b)$ are a Pythagorean triple?

Is there exist postive integer $a,b,c,x,y,p,q$,such $(a,b,c),(x,y,a),(p,q,b)$ are a Pythagorean triple?

I.e $$\begin{cases} a^2+b^2=c^2\\ x^2+y^2=a^2\\ p^2+q^2=b^2 \end{cases}$$ have postive integers solution?