The earlier semi-direct product construction can now be applied to the functor $\phi$. The objects of $\mathbb{F}_{\phi}$ are just the objects of $\mathcal{D}$ (as an extension of considering a monoid a category with a single object) but a morphism $$ X\rightarrow Y$$ is a triple $$(f, I , n),$$$$(f, S , n),$$ where $f:X \rightarrow Y $ is a morphism in $\mathcal{D}$, $I\in \phi(X)$$S\in \phi(X)$, and $n\in \mathbb{N}_{\geq 1}$. If $Y\rightarrow Z$ is given by the triple $(g, J, m)$$(g, T, m)$, then the composition is defined by $$(g, J, m)(f, I, n)= (g\circ f, f^*(J)+mI, mn).$$$$(g, T, m)(f, S, n)= (g\circ f, f^*(S)+mT, mn).$$
Up to here is pretty elementary. But some confusion may arise from the fact that the general Frobenioid involves yet another category $\mathcal{C}$ equipped with a functor $ \mathcal{C}\rightarrow \mathbb{F}_{\phi}$. In fact, $\mathcal{C}$ is in many ways more fundamental than $\mathbb{F}_{\phi}$ and should be thought of as a fiber bundle over the base $\mathbb{F}_{\phi}$, as $\mathbb{F}_{\phi}$ is fibered over $\mathcal{D}$. That is, we have a composition of fibrations
$$\mathcal{C}\rightarrow \mathbb{F}_{\phi}\rightarrow \mathcal{D}.$$
The nature of $\mathcal{C}$ is clarified by the main example, whereby $\mathcal{C}$ is associated to multiplicative groups of rational functions on varieties. The abstract framework for this example, is that of a model Frobenioid, which one constructs out of yet another functor $\psi: \mathcal{D}\rightarrow Ab$ to abelian groups together with a map of functors $$Div:\psi \rightarrow \phi^{gp},$$ where $\phi^{gp}$ denotes the group completion of $\phi$ in an obvious sense. (As the notation suggests, the example to keep in mind is the homomorphism from rational functions to divisors.) Out of this data, we form the category $\mathcal{C}$ whose objects are pairs $$(X, \alpha),$$ with $X$ an object of $\mathcal{D}$ and $\alpha\in \phi(X)^{gp}$. A map from $(X, \alpha)$ to $(Y, \beta)$ is then a quadruple $$(f, I, n, u)$$$$(f, S, n, u)$$ where $f: X\rightarrow Y$ is a morphism in $\mathcal{D}$, $I\in \phi(X)$, $n \in \mathbb{N}_{\geq 1}$, $u\in \psi(X)$, and $$n\alpha+I=f^*(\beta)+Div(u).$$$$n\alpha+S=f^*(\beta)+Div(u).$$ We have merely added the components $\alpha$ to the objects and the components $u$ to the morphisms. There is thus an obvious projection functor to $\mathbb{F}_{\phi}$. The number $n$, by the way, is referred to as the Frobenius degree of the morphism, and seems to be eventually very important.
--Now consider a morphism of the form $(Id_X, I, 1, 1)$$(Id_X, S, 1, 1)$. Of course we must have $Y=X$ and $\alpha+I=\beta$$\alpha+S=\beta$. Thus, this is the `tensor product map' from $(X,\alpha)$ to $(X, \alpha+I)$$(X, \alpha+S)$.
--A morphism of the form $(Id_X, 0, n, 1)$ from $(X,\alpha)$ to $(X,\beta)$ imposes $n\alpha=\beta$. So we have formally adjoined a map from a line bundle to its $n$-th tensor power. My impression is that these `Frobenius-type' maps play a very important role.