The 4-sphere $S^4$ cannot be a symplectic manifold. In particular, it does not admit an atlas whose transition maps are symplectomorphisms $(\mathbb{R}^4,\omega_0)\to(\mathbb{R}^4,\omega_0)$$(\mathbb{R}^4,\omega_\text{std})\to(\mathbb{R}^4,\omega_\text{std})$. A theorem of Eliashberg-Gromov statesproved that if the $C^0$-limit of symplectomorphisms is a diffeomorphism, then it is a symplectomorphism. We should thencan now ask about the next best thing:
Does $S^4$ have a symplectohomeomorphic structure, i.e. are there charts (equipped with the standard symplectic form on $\mathbb{R}^4$) whose transition maps are homeomorphisms that are $C^0$-limits of symplectomorphisms?
(This question should be credited tomay have originated from Alan Weinstein, who I heardtold me it from after conversations aboutconcerning symplectic rigidity.)