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Let $f$$v\not= 1$ be a real number. Let $f(s)$ be real analytic function withon an open interval containing $s=1$ as$v$ and $1$, with a zero of order $m$. Let$m\ge 1$ at $v$ be a real number$s=1$.

My question is: SolveCan we solve this functional equation with respect to $f$:

$$f(sv)=\frac{(s-1)f′(s)}{f(s)}$$$$f(sv)=\frac{(s-1)f'(s)}{f(s)}$$ where $s$ is in the proximity of $s=1$.

Let $f$ be a real analytic function with $s=1$ as a zero of order $m$. Let $v$ be a real number.

My question is: Solve this functional equation with respect to $f$:

$$f(sv)=\frac{(s-1)f′(s)}{f(s)}$$ where $s$ is in the proximity of $s=1$.

Let $v\not= 1$ be a real number. Let $f(s)$ be real analytic on an open interval containing $v$ and $1$, with a zero of order $m\ge 1$ at $s=1$.

My question is: Can we solve this functional equation with respect to $f$:

$$f(sv)=\frac{(s-1)f'(s)}{f(s)}$$ where $s$ is in the proximity of $s=1$.

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Safwane
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Solve this functional equation with respect to $f$

Let $f$ be a real analytic function with $s=1$ as a zero of order $m$. Let $v$ be a real number.

My question is: Solve this functional equation with respect to $f$:

$$f(sv)=\frac{(s-1)f′(s)}{f(s)}$$ where $s$ is in the proximity of $s=1$.