Timeline for A sequence of subsets of an infinite group
Current License: CC BY-SA 3.0
13 events
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Apr 13, 2017 at 12:19 | history | edited | CommunityBot |
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Aug 23, 2014 at 23:48 | answer | added | Anton Klyachko | timeline score: 2 | |
Aug 23, 2014 at 10:42 | comment | added | Anton Klyachko | A related question: mathoverflow.net/q/179177/24165 . | |
Jul 6, 2014 at 19:31 | answer | added | YCor | timeline score: 5 | |
Jul 6, 2014 at 12:08 | comment | added | user44191 | Masked Avenger: yes, I meant to include that; I meant to replace only the second condition (i.e. we have $A_n = A_n^{-1}, A_{n + 1}A_{n + 1} \subseteq A_n, A_{n + 1} \subsetneq A_n$. | |
Jul 6, 2014 at 8:25 | comment | added | YCor | @Misha I'm not sure of any link with approximate groups, which involve a parameter and finite subsets. On the other hand there should be a link with non-topologizable groups. | |
Jul 6, 2014 at 3:47 | comment | added | Misha | It seems that the question is related to the concept of "approximate groups". Alas, I do not know much about the area, but Terry Tao might be able to say something interesting. | |
Jul 6, 2014 at 0:45 | comment | added | H. Khas | Clearly all $A_n$ contain $1$ and $\bigcap _{n}A_n$ is a subgroup. | |
Jul 6, 2014 at 0:34 | comment | added | The Masked Avenger | I am not sure of the equivalence. I think closure under inverse is important (consider riffs on N under min). | |
Jul 5, 2014 at 23:49 | comment | added | user44191 | It's equivalent to say that $A_{n + 1} \subsetneq A_n, A_{n + 1} A_{n +1} \subseteq A_n$, by going through $A_{2n}$. | |
Jul 5, 2014 at 23:15 | history | edited | H. Khas | CC BY-SA 3.0 |
added 5 characters in body
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Jul 5, 2014 at 22:59 | comment | added | The Masked Avenger | Such a group has to be torsion. | |
Jul 5, 2014 at 21:30 | history | asked | H. Khas | CC BY-SA 3.0 |