Timeline for Conditions for a parametric curve to avoid self-intersection?
Current License: CC BY-SA 3.0
6 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Jun 8, 2014 at 15:06 | comment | added | janowski | have edited my answer to avoid the impression that it was tautological | |
| Jun 8, 2014 at 15:05 | history | edited | janowski | CC BY-SA 3.0 |
edited on account of a commenz
|
| Jun 8, 2014 at 13:10 | comment | added | janowski | True, but the point of my remark was that this condition depends only on ONE function $f$, rather than on the pair of functions $x$ and $y$. I should probably have written $$\int^s f(u)dt \neq \int^t f(u)du.$$ | |
| Jun 8, 2014 at 9:43 | comment | added | Marco Golla | Just a small remark: the condition in point 1 is actually independent of the fact that $F$ is a primitive of $f$. | |
| Jun 8, 2014 at 7:12 | review | First posts | |||
| Jun 8, 2014 at 7:14 | |||||
| Jun 8, 2014 at 6:53 | history | answered | janowski | CC BY-SA 3.0 |