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igvenGiven the idvergentdivergent integral

$$ \int _{0}^{\infty}dx \int_{0}^{\infty}dy \frac{x^{2}y+1}{1+x+y} $$

how could ican I apply Hadamard's fintefinite part to give a finite meaning to it ?

itIt is jusjust made by applying htethe itetrated finite part first to 'dx''$dx$' and then 'dy''$dy$'?

igven the idvergent integral

$$ \int _{0}^{\infty}dx \int_{0}^{\infty}dy \frac{x^{2}y+1}{1+x+y} $$

how could i apply Hadamard's finte part to give a finite meaning to it ?

it is jus made by applying hte itetrated finite part first to 'dx' and then 'dy'?

Given the divergent integral

$$ \int _{0}^{\infty}dx \int_{0}^{\infty}dy \frac{x^{2}y+1}{1+x+y} $$

how can I apply Hadamard's finite part to give a finite meaning to it ?

It is just made by applying the itetrated finite part first to '$dx$' and then '$dy$'?

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double integral and Hadamard finite part

igven the idvergent integral

$$ \int _{0}^{\infty}dx \int_{0}^{\infty}dy \frac{x^{2}y+1}{1+x+y} $$

how could i apply Hadamard's finte part to give a finite meaning to it ?

it is jus made by applying hte itetrated finite part first to 'dx' and then 'dy'?