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added missing word "equivalence" in "f is a homotopy equivalence"
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Is there a (non-Abelian) homology theory that realizes the following:

Let $X,Y$ be manifolds with complexes $C(X),C(Y)$. Then $X$ and $Y$ are homotopy-equivalent if and only if $C(X)$ and $C(Y)$ are isomorphic.

Or maybe, the following? ("You need the map...")

Let $X,Y$ be manifolds with complexes $C(X),C(Y)$. Let $f:X\to Y$ be a continuous map which induces the "chain map" $f_*:C(X)\to C(Y)$. Then $f$ is a homotopy equivalence (it admits a $g:Y\to X$ such that $fg$ and $gf$ are homotopic to the identities) if and only if $f_*$ is an isomorphism.

If yes: which one/ones? An introduction to such theory?

If no: not yet, or is it impossible? Why?

No restriction for the objects in the complexes, they can be groups, modules, groupoids, anything else.

Of course, $X,Y$ may be required to be "nice enough" for the above to work. So, please state also the technical requirements. Moreover:

Same questions, but with cohomology instead of homology?

Is there a (non-Abelian) homology theory that realizes the following:

Let $X,Y$ be manifolds with complexes $C(X),C(Y)$. Then $X$ and $Y$ are homotopy-equivalent if and only if $C(X)$ and $C(Y)$ are isomorphic.

Or maybe, the following? ("You need the map...")

Let $X,Y$ be manifolds with complexes $C(X),C(Y)$. Let $f:X\to Y$ be a continuous map which induces the "chain map" $f_*:C(X)\to C(Y)$. Then $f$ is a homotopy (it admits a $g:Y\to X$ such that $fg$ and $gf$ are homotopic to the identities) if and only if $f_*$ is an isomorphism.

If yes: which one/ones? An introduction to such theory?

If no: not yet, or is it impossible? Why?

No restriction for the objects in the complexes, they can be groups, modules, groupoids, anything else.

Of course, $X,Y$ may be required to be "nice enough" for the above to work. So, please state also the technical requirements. Moreover:

Same questions, but with cohomology instead of homology?

Is there a (non-Abelian) homology theory that realizes the following:

Let $X,Y$ be manifolds with complexes $C(X),C(Y)$. Then $X$ and $Y$ are homotopy-equivalent if and only if $C(X)$ and $C(Y)$ are isomorphic.

Or maybe, the following? ("You need the map...")

Let $X,Y$ be manifolds with complexes $C(X),C(Y)$. Let $f:X\to Y$ be a continuous map which induces the "chain map" $f_*:C(X)\to C(Y)$. Then $f$ is a homotopy equivalence (it admits a $g:Y\to X$ such that $fg$ and $gf$ are homotopic to the identities) if and only if $f_*$ is an isomorphism.

If yes: which one/ones? An introduction to such theory?

If no: not yet, or is it impossible? Why?

No restriction for the objects in the complexes, they can be groups, modules, groupoids, anything else.

Of course, $X,Y$ may be required to be "nice enough" for the above to work. So, please state also the technical requirements. Moreover:

Same questions, but with cohomology instead of homology?

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geodude
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Is there a homology theory that gives a *necessary and sufficient* condition for homotopy equivalence?

Is there a (non-Abelian) homology theory that realizes the following:

Let $X,Y$ be manifolds with complexes $C(X),C(Y)$. Then $X$ and $Y$ are homotopy-equivalent if and only if $C(X)$ and $C(Y)$ are isomorphic.

Or maybe, the following? ("You need the map...")

Let $X,Y$ be manifolds with complexes $C(X),C(Y)$. Let $f:X\to Y$ be a continuous map which induces the "chain map" $f_*:C(X)\to C(Y)$. Then $f$ is a homotopy (it admits a $g:Y\to X$ such that $fg$ and $gf$ are homotopic to the identities) if and only if $f_*$ is an isomorphism.

If yes: which one/ones? An introduction to such theory?

If no: not yet, or is it impossible? Why?

No restriction for the objects in the complexes, they can be groups, modules, groupoids, anything else.

Of course, $X,Y$ may be required to be "nice enough" for the above to work. So, please state also the technical requirements. Moreover:

Same questions, but with cohomology instead of homology?