Timeline for Conceptual explanation for the relationship between Clifford algebras and KO
Current License: CC BY-SA 3.0
8 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Oct 28, 2014 at 23:34 | comment | added | Qiaochu Yuan | @Callan: there's a sign issue somewhere near the beginning. If you want the defining relation to be $v \otimes v = q(v)$ then $\text{Cl}_1$ is not $\mathbb{C}$ but $\mathbb{R} \times \mathbb{R}$. | |
| Sep 13, 2013 at 22:31 | answer | added | Charles Rezk | timeline score: 23 | |
| Aug 7, 2013 at 15:21 | comment | added | David White | Yeah, we covered that more thoroughly in the course (as you can imagine, Hovey knows a lot about this), but I got sick of writing in that answer at some point. Anyway, if this thread lingers for awhile without an answer I can go dig out my notes from that course and try to write a bit more | |
| Aug 7, 2013 at 15:10 | comment | added | Callan McGill | @David Thank you for the link. The "magic" you explain in your answer is some of the inspiration for the question. | |
| Aug 7, 2013 at 11:59 | comment | added | Anton Fetisov | A similar question: mathoverflow.net/questions/85516/… | |
| Aug 7, 2013 at 7:09 | answer | added | Urs Schreiber | timeline score: 11 | |
| Aug 7, 2013 at 1:32 | comment | added | David White | Hi Callan. I wrote something about this at a previous MO post: mathoverflow.net/questions/129199/…. Probably you're well beyond the level where this could help you, but just in case I thought I'd mention it | |
| Aug 7, 2013 at 0:00 | history | asked | Callan McGill | CC BY-SA 3.0 |