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David
David
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How do we showIt is known that every AI-algebra (i.e. inductive limit of interval algebras) is an AT-algebra (i.e. inductive limit of circle algebras)?

This seems a little bit odd because a building block of an AT-algebra can be embedded in a building block of an AI-algebra. Is there any example to clarify this?

How do we show that every AI-algebra (i.e. inductive limit of interval algebras) is an AT-algebra (i.e. inductive limit of circle algebras)?

This seems a little bit odd because a building block of an AT-algebra can be embedded in a building block of an AI-algebra.

It is known that every AI-algebra (i.e. inductive limit of interval algebras) is an AT-algebra (i.e. inductive limit of circle algebras)?

This seems a little bit odd because a building block of an AT-algebra can be embedded in a building block of an AI-algebra. Is there any example to clarify this?

Source Link
David
David
  • 169
  • 4

All AI-algebras are AT-algebras

How do we show that every AI-algebra (i.e. inductive limit of interval algebras) is an AT-algebra (i.e. inductive limit of circle algebras)?

This seems a little bit odd because a building block of an AT-algebra can be embedded in a building block of an AI-algebra.