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Jun 25, 2013 at 3:02 review First posts
Jun 25, 2013 at 13:29
Jun 13, 2013 at 2:09 vote accept Yog_Shohoth
Jun 4, 2013 at 13:43 comment added Zev Chonoles Originally posted on math.SE: math.stackexchange.com/q/402350/264
Jun 4, 2013 at 7:33 answer added Boris Novikov timeline score: 0
Jun 4, 2013 at 5:40 comment added HJRW Since you don't put any constraints on the way that $\lambda$ and $i$ interact with the operation on $V$, you can just choose any bijection between any $G\subset\chi(V,V)$ and any group.
Jun 4, 2013 at 4:13 history asked Yog_Shohoth CC BY-SA 3.0