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If $(X,d)$ is a metric space, then we say that a closed subset $A$ of $X$ is a z-set if for each number $k\gt 0$ there is a continuous map $f_k$ from $X$ into $X-A$ such that $d(x,f_k(x))\lt k$.

I am wondering if a z-set in the Hilbert cube is a deformation retract of it?

If $(X,d)$ is a metric space, then we say that a closed subset $A$ of $X$ is a z-set if for each number $k\gt 0$ there is a continuous map $f_k$ from $X$ into $X-A$ such that $d(x,f_k(x))\lt k$.

I am wondering if an AR which is a z-set in the Hilbert cube is a deformation retract of it?

If $(X,d)$ is a metric space, then we say that a closed subset $A$ of $X$ is a z-set if for each number $k>0$ there is a continuous map $f_k$ from $X$ into $X-A$ such that $d(x,f_k(x))\lt k$.

I am wondering if a z-set in the Hilbert cube is a deformation retract of it?

If $(X,d)$ is a metric space, then we say that a closed subset $A$ of $X$ is a z-set if for each number $k\gt 0$ there is a continuous map $f_k$ from $X$ into $X-A$ such that $d(x,f_k(x))\lt k$.

I am wondering if a z-set in the Hilbert cube is a deformation retract of it?