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Dominic van der Zypen's user avatar
Dominic van der Zypen's user avatar
Dominic van der Zypen's user avatar
Dominic van der Zypen
  • Member for 14 years, 4 months
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Infinite Hausdorff space that is not homeomorphic to any proper quotient
Oh, possibly, have to think about it. Please post your example as an answer
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Lattice: Join of orthogonal elements is set union?
So $(\cdot)^{\perp\perp}$ is a closure operation, and you consider the sets closed under that operation? And what does it mean that $A\perp B$?
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Critical topological spaces
Excellent results -- thanks Joseph!
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